Nilai dari limx→0x3−16x+12x2+4x+6=....\lim\limits_{x\to0}\frac{x^3-16x+12}{x^2+4x+6}=....x→0limx2+4x+6x3−16x+12=....
222
−1-1−1
333
12\frac{1}{2}21
13\frac{1}{3}31