Pernyataan yang tepat jika alogf(x)>alogg(x)^a\log f\left(x\right)>^a\log g\left(x\right)alogf(x)>alogg(x) dimana a>1a>1a>1 adalah ....
f(x)>g(x)f\left(x\right)>g\left(x\right)f(x)>g(x)
f(x)<g(x)f\left(x\right)<g\left(x\right)f(x)<g(x)
f(x)=g(x)f\left(x\right)=g\left(x\right)f(x)=g(x)
f(x)≤g(x)f\left(x\right)\le g\left(x\right)f(x)≤g(x)
f(x)≥g(x)f\left(x\right)\ge g\left(x\right)f(x)≥g(x)