Diketahui ∑k=510k3=2.925\sum_{k=5}^{10}k^3=2.925∑k=510k3=2.925. Nilai dari ∑k=611(k3−3k2+3k−1)\sum_{k=6}^{11}\left(k^3-3k^2+3k-1\right)∑k=611(k3−3k2+3k−1) adalah....
9.252
2.925
5.922
9.225
2.952