Bentuk sederhana dari 42+84\sqrt{2}+\sqrt{8}42+8 adalah...
626\sqrt{2}62
525\sqrt{2}52
323\sqrt{2}32
222\sqrt{2}22
Ingat rumus bentuk akar : acn±bcn=a±bcna\sqrt[n]{c}\pm b\sqrt[n]{c}=a\pm b\sqrt[n]{c}anc±bnc=a±bnc
Maka,
42+8=42+4×24\sqrt{2}+\sqrt{8}=4\sqrt{2}+\sqrt{4\times2}42+8=42+4×2
=42+(4×2)=4\sqrt{2}+(\sqrt{4}\times\sqrt{2})=42+(4×2)
=42+(2×2)=4\sqrt{2}+(2\times\sqrt{2})=42+(2×2)
=42+22=4\sqrt{2}+2\sqrt{2}=42+22
=(4+2)2=\left(4+2\right)\sqrt{2}=(4+2)2
=62=6\sqrt{2}=62