Himpunan penyelesaian dari 13log(x2−2x−3)≥13log(x2+4x−12)^{\frac{1}{3}}\log\left(x^2-2x-3\right)\ge^{\frac{1}{3}}\log\left(x^2+4x-12\right)31log(x2−2x−3)≥31log(x2+4x−12) adalah ....
HP={x ∣ x >3 , xϵR }HP=\left\{x\ |\ x\ >3\ ,\ x\epsilon R\ \right\}HP={x ∣ x >3 , xϵR }
HP={x ∣ <−6<x<3}HP=\left\{x\ |\ <-6<x<3\right\}HP={x ∣ <−6<x<3}
HP={x ∣ −1<x<3}HP=\left\{x\ |\ -1<x<3\right\}HP={x ∣ −1<x<3}
HP={x ∣ 32<x <2 , xϵR }HP=\left\{x\ |\ \frac{3}{2}<x\ <2\ ,\ x\epsilon R\ \right\}HP={x ∣ 23<x <2 , xϵR }
HP={x ∣ x ≥32, xϵR}HP=\left\{x\ |\ x\ \ge\frac{3}{2},\ x\epsilon R\right\}HP={x ∣ x ≥23, xϵR}