Himpunan penyelesaian dari 18log(4x−1128)>2^{\frac{1}{8}}\log\left(4x-\frac{1}{128}\right)>281log(4x−1281)>2 dalah ....
HP={x ∣ 1512<x<3512}HP=\left\{x\ |\ \frac{1}{512}<x<\frac{3}{512}\right\}HP={x ∣ 5121<x<5123}
HP={x ∣x< 1512dan x>3512}HP=\left\{x\ |x<\ \frac{1}{512}\text{dan}\ x>\frac{3}{512}\right\}HP={x ∣x< 5121dan x>5123}
HP={x ∣ x>1512}HP=\left\{x\ |\ x>\frac{1}{512}\right\}HP={x ∣ x>5121}
HP={x ∣ x<3512}HP=\left\{x\ |\ x<\frac{3}{512}\right\}HP={x ∣ x<5123}
HP={x ∣ x>3512}HP=\left\{x\ |\ x>\frac{3}{512}\right\}HP={x ∣ x>5123}