Hasil dari ∫(4x5−1)2x6−3x dx adalah ....
92(2x6−3x)2x6−3x+C
20x4(2x6−3x)2x6−3x+C
2x(2x6−3x)2x6−3x+C
91(2x6−3x)2x6−3x+C
9(2x6−3x)2x6−3x+C