Selesaikan persamaan eksponensial berikut!
42x+4 = 5⋅41x4^{\frac{2}{x}}+4\ =\ 5\cdot4^{\frac{1}{x}}4x2+4 = 5⋅4x1
x = 1 atau x = 0x\ =\ 1\ atau\ x\ =\ 0x = 1 atau x = 0
x = 1x\ =\ 1x = 1
x = 0x\ =\ 0x = 0
x = 2x\ =\ 2x = 2
x = 5x\ =\ 5x = 5