kejarcita | Merdeka Belajar Merdeka Mengajar

# 8

Pilgan

Diberikan fungsi $h (x) = tan^{3} (6 x - 8) - sec^{3} (9 x + 2)$ . Turunan pertama fungsi tersebut adalah ....

$6 tan^{2} (6 x - 8) sec^{2} (6 x - 8) - 9 sec^{3} (9 x + 2) tan (9 x + 2)$

$6 tan^{2} (6 x - 8) sec^{2} (6 x - 8) + 9 sec^{3} (9 x + 2) tan (9 x + 2)$

$18 tan^{2} (6 x - 8) sec^{2} (6 x - 8) - 27 sec^{3} (9 x + 2) tan (9 x + 2)$

$18 tan^{2} (6 x - 8) sec^{2} (6 x - 8) + 27 sec^{3} (9 x + 2) tan (9 x + 2)$

$18 tan^{2} (6 x - 8) sec^{2} (6 x - 8) - 27 sec^{2} (9 x + 2) tan (9 x + 2)$